Question

Find the greatest number of four digits which when
divided by 10, 11, 15 and 22 leaves 3, 4, 8 and 15
as remainders, respectively,
​

Answer 1

Answer:

(10−3)=(11−4)=(15−8) =(22−15)=7

Therefore, the following method can be applied.

LCM(10,11,15,22) = 330

divide the four digit largest number i.e 9999 by 330

you will get 99 as remainder

Now, subtract 99 from 9999.

we have ,

9999-99= 9900

Now subtract number 7 from 9900

i.e 9900−7=9893

Hence answer is 9893.

Step-by-step explanation:

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