Find the greatest number of four digits which when divided by 10 11 15 and 22 leaves remainder 3,4,8,and 15 respectively
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heya genuis your answer is here
Solution
(10−3)=(11−4)=(15−8)(10−3)=(11−4)=(15−8) =(22−15)=7=(22−15)=7
Therefore, the following method can be applied.
LCM(10,11,15,22)=330LCM(10,11,15,22)=330
9999/3309999/330 gives remainder of 9999
9999−99=99009999−99=9900
i.e., largest 44 digit multiple of 330330 is 99009900
9900−7=98939900−7=9893
Hence answer is 98939893
Solution
(10−3)=(11−4)=(15−8)(10−3)=(11−4)=(15−8) =(22−15)=7=(22−15)=7
Therefore, the following method can be applied.
LCM(10,11,15,22)=330LCM(10,11,15,22)=330
9999/3309999/330 gives remainder of 9999
9999−99=99009999−99=9900
i.e., largest 44 digit multiple of 330330 is 99009900
9900−7=98939900−7=9893
Hence answer is 98939893
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