Question

find the greatest number of six digit exactly divisible by 18 ,24,36​

Answer 1

Hey mate here is your answer:-

The greatest six digit number is :- 999999

The LCM Of = 63

99999-63 = 999963

The greatest six digit number exactly divisble by 18,24,36 is :- 999936

999936 ÷ 18 = 55552

999936 ÷ 24 = 41664

999936 ÷ 36 = 27776

-------------------------

Ans:- 999936

-------------------------

Please mark me as brainliest!!

Answer 2

Question:

Find the greatest number of six digit exactly divisible by 18,24 and 36.

Answer:

The number that is exactly divisible by 18,24 and 36 should be their LCM.

We find their LCM by prime factorization:

$18 = 2 \times 3 {}^{2} \\ 24 = 2 {}^{3} \times 3 \\ 36 = 2 {}^{2} \times 3 {}^{2}$

The LCM is:

$2 {}^{3} \times 3 {}^{2} = 8 \times 9 = 72$

Largest six digit number is 999999.

Dividing 999999 by 72,we get a remainder of 63.

Subtracting 63 from 999999.

We obtain 999936

Hence,999936 is largest six digit number divisible by 18,24 and 36