Question

find the greatest number of six digit which is perfect square .find the square root of this number ​

Answer 1

Answer:

998001

Step-by-step explanation:

HIT LIKE 5 STAR MAY FOLLOW

Answer 2

Answer:

$\huge\rm{Solution} \:$

$\rm{ greatest \: 6 - digit \: number \: is \: } \\ \rm{ 999999}$

$\rm{ (finding \: square \: root \: of \: this \: number} \\ \rm{ by \: using \: long \: division \: method)} \:$

$\rm{ since \: remainder \: is \: 1998}$

$\rm{(999 {)}^{2} < 999999 }$

$\rm{ subtract \: 1998 \: from \: 999999}$

$\rm{ i.e \: \: 999999 - 1998} \\ \rm{ = 998001 }$

$\rm{ required \: greatest \: 6 \: digit \: number \: } \\ \rm{ is \: 998001}$

$\rm{ now \: finding \: square \: root \: of \: this} \\ \rm{ number}$

$\rm{ \sqrt{998001} = 999}$

Step-by-step explanation:

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