Question

find the greatest number of six digits exactly divisible by 18, 24,36

Answer 1

first find the lcm of 18,24and36 i.e. 72 and then find the greatest 6 digit no. i.e. 999999 so required no. is 999999-72 = 999927 is ur ans.

Answer 2

LCM of 18,24 and 36

18 = 2 × $\bf\huge3^{2}$

24 = $\bf\huge2^{3}$ × 3

36 = $\bf\huge2^{2}$ ×  $3^{2}$

LCM (18,24,36) =  $\bf\huge2^{3}$ $\bf\huge3^{2}$

= 72

Largest 6 digit number is 999999

Now divide 999999 by 72

You will get 63 as remainder

Required Number = 999999 – 63  

= 999936