Find the greatest number of six digits which on dividing by 8 16 24 36 and 48 leave remainder 7 in each case
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Step-by-step explanation:
But we have a condition that it leaves a remainder of 7. So we add 7 to the LCM (144+7=151). Hence the smallest number that when divided by 12 16 24 and 36 leaves a remainder 7 is 151.
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