Question

Find the greatest number of six digits which
on division by 42, 45, 48, 56 and 60 leaves 12
ss remainder in each case,​

Answer 1

Answer:

Find the LCM of the divisors required.  

LCM of 42, 45, 48, 56 and 60 = 5040.  

Find the largest 6 digit multiple of 5040.  

The largest 6 digit number is 999999.  

999999 divided by 5040 gives quotient 198 and remainder 2079.  

So 5040 x 198 = 999999 - 2079 = 997920 is the largest 6 digit multiple of 5040.  

Add the remainder 12 which is required in the question.  

997920 + 12 = 997932.  

∴ 997932 is the answer.  

If any doubt, divide 997932 by the divisors required. If the same remainder 12 is gotten, it's the right answer. If not, I failed!

Step-by-step explanation:

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