Math, asked by re89kh, 1 year ago

Find the greatest number of six digits which on division by 42,45,48,56 and 60 leaves 12 as remainder in each case.

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Answered by Aditya1612004

3

FIND LCM OF ALL THESE THEN DIVIDE 999999 BY LCM ,SUBTRACT REMAINDER AND THE ADD 12 THIS IS THE ANSWER. PLS MARK BRAINLIEST

Answered by brajmohank94

4

Hope it help u

plz mark as a brainliest

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