Question

find the greatest number of six which on being divided by 6 7 8 9 and 10 leaves 4 5 6 7and 8 as remainder respectively
(hint greatest 6 digit number
=999999
I need this answer fast ​​

Answer 1

Answer:

hi it is a nice question

Answer 2

Answer:

997920

Step-by-step explanation:

First we need to find the common difference between divisors and remainders

Here it is 2

• 6-4= 2
• 7-5=2
• 10-8=2

And the common number of all divisors is obtained by taking LCM of 6,7,8,9,10

LCM of divisors is 2³x3²x5x7 = 2520

now divide the greatest 6 digit number 999999 by 2520 and subtract the remainder from the largest 6 digit number

• 999999 divided by 2520 leaves a remainder of 2079
• so subtract 2079 from 999999
• which gives 997920

Now this number when divided by 6,7,8,9,10 leaves remainders of 4,5,6,7,8.

Hope this helps you.