find the greatest number of the Pythagorean triplet two of whose members are 24 and 143
Answers
Answered by
6
pytahgorean tripplet =2m,m^2-1 and m^2+1
here 2m=24
m=12
m^2-1=(12)^2-1=144-1=143
m^2+1=(12)^2+1=144+1=145
=145 ans
hope it helps
here 2m=24
m=12
m^2-1=(12)^2-1=144-1=143
m^2+1=(12)^2+1=144+1=145
=145 ans
hope it helps
Answered by
1
here is your answer.
hope it will help you.
Attachments:
Similar questions