Find the greatest number that divides 149 and 101, leaving a remainder of 5 in each case.
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Answer:
48 is greatest number which divides both number 149 and 101 and leaving remainder 5.
Step-by-step explanation:
Let us take two numbers as N and M
N = 149 – 5 = 144
M = 101 – 5 = 96
Now subtracting 5 from the number we get 144 and 96.
Now to find largest number which divides both the number and to leave remainder 5 , HCF can be used.
Using factorization method we get
144= 2x2x2x2x3x3
96=2x2x2x2x2x3
Common factors are 2x2x2x2x3=48
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