Question

find the greatest number that divides 249 and 309 leaving remainder 9

Answer 1

Step-by-step explanation:

249-9=240

309-9=300

hcf of 240=2×2×2×2×3×5

300=2×2×3×5×5

hcf = 2×2×3×5

=60

Answer 2

The greatest number that divides 249 and 309 leaving remainder 9 is 60.

Given:

The numbers 249 and 309

To find:

The greatest number that divides 249 and 309 leaving remainder 9

Solution:

To get the greatest number, we have to find out H.C.F

Remainder is to be subtracted from the numbers to find out H.C.F so that when original numbers are divided by H.C.F, they leaves the remainder 9.

Numbers whose H.C.F is to be calculated are:

249-9 = 240

309-9 = 300

Finding H.C.F by prime factorisation method

240 = 2*2*2*2*3*5

300 = 2*2*3*5*5

H.C.F = 2*2*3*5 = 60

So, the greatest number that divides 249 and 309 leaving remainder 9 is 60.

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