Find the greatest number that divides 255,630 and 1300 leaving a remainder of 5,10 and 50 respectively
Answers
Answered by
2
Answer:
10
Step-by-step explanation:
HCF of 255, 630, 1300 divides each of the numbers without leaving a remainder.
255-5= 250
630-10= 620
1300-50= 1250
HCF of 250, 620 and 1250 is exactly divisible leaning a remainder of 5, 10, 50 respectively.
The HCF is 10
Ans: The required number is 10.
Similar questions