Question

pls give me a answerpls​

Answer 1

Answer:

Answer is option b} 36

Step-by-step explanation:

$(3 + 2 \sqrt{2 } + \frac{1}{3 +2 \sqrt{2} } ) ^{2}$

$( \frac{3 + 2 \sqrt{2} \times 3 + 2 \sqrt{2} + 1}{3 + 2 \sqrt{2} } ) {}^{2}$

$( \frac{17 + 12 \sqrt{2} + 1}{3 + 2 \sqrt{2} } )^{2}$

$( \frac{18 + 12 \sqrt{2} }{3 + 2 \sqrt{2} } )^{2}$

Now, taking 6 common in numerator.

$( \frac{6(3 + 2 \sqrt{2} }{3 + 2 \sqrt{2} } )^{2}$

Here, 3+2√2 will be cancelled.

$(6)^{2}$

$36$

Therefore the answer is 36. Option b.