Find the greatest number that divides 79115 and 163, leaving remainder 7 in each case
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Step-by-step explanation:
Given:79, 115 and 163
To find:Find the greatest number that divides 79, 115 and 163, leaving remainder 7 in each case.
Solution:
Step 1: Subtract 7 from both numbers
79-7=72
115-7=108
163-7=156
Step2: Find HCF of 72,108,156
72=2×2×2×3×3
108=2×2×3×3×3
156=2×2×3×13
HCF(72,108,156)=2×2×3
HCF(72,108,156)=12
Final answer:
The greatest number is 12 that divides 79,115 and 163, leaving remainder 7 in each case.
Hope it helps you.
To learn more on brainly:
Find the greatest number that will divide 55,75,113 leaving the remainder 7,3,5 respectively
https://brainly.in/question/46009045
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