find the greatest number that divides 846,1107,and 1238 leaving remainders of 1,2, and 3 respectively
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Answered by
7
Answer:
65
Step-by-step explanation:
the greatest number that divides 846, 1107, and 1238 leaving 1,2 and 3 as remainder respectively
it is nothing but the HCF of(846-1)(1107-2)(1238-3)
i.e. HCF of 845,1105,1235.
which is 13*5= 65
hope this helped
hail hydra.
Answered by
0
Greatest number = HCF of 846,1107and1238
(846-1 )-----(1107-2)-------(1238-3)
Which is 13*5=65
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