Math, asked by krishagarwal267, 9 months ago

FIND THE GREATEST NUMBER THAT DIVIDES THE 20,30 and 40 LEAVING REMAINDER 2,6 AND 4 RESPECTIVELY....
PLZ...URGENT...
....FULL SOLUTION....​

Answers

Answered by squeen123
13

Answer:

6

Step-by-step explanation:

20 - 2 = 18

30 - 6 = 24

40 - 4 = 36

18 = 3x3x2

24 = 2x2x2x3

36 = 2x2x3x3

therefore HCF(18,24,36) = 3x2

                                        = 6

THEREFORE THE GREATEST NUMBER THAT DIVIDES THE 20,30 and 40 LEAVING REMAINDER 2,6 AND 4 IS 6.

Answered by abhinavsingh128
8

Answer:

this is the answer of ur question

plz follow me anyone aur haan

mera answer brainliest kar dena

Attachments:
Similar questions