Question

find the greatest number that will divide 121, 33 and 55 leaving the remainders 1, 3 and 5 respectively

Answer 1

Answer:

10

Step-by-step explanation:

120-2x2x2x5x3

30-2x5x3

50-2x5-10

HCF-2x5-10

Answer 2

Answer:

Hey friend,

Here is the answer you are searching for,

121-1=120

33-3=30

55-5=50

Required number = HCF of 120,30,50 = 10

Therefore,

Greatest number that will divide 121, 33 and 55 leaving the remainders 1, 3 and 5 = 10

Step-by-step explanation:

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