How is carbolic acid prepared from the
following compounds
1.aniline 2. Chiorobenzene
Answers
1) Aniline: C6H5NH2 to Carbolic acid(Phenol-Hydroxybenzene)
Steps involved:
a) Convert Aniline to Benzene Diazonium chloride with NaNO2 and HCl.
(NaNO2+HCl)
(Aniline) C6H5NH2------------------> C6H5N2Cl (Benzene Diazonium chloride)
b)Convert Diazonium salt to Phenol by heating with water in dil. H2SO4.
water and heat
C6H5N2Cl----------------------> C6H5OH (phenol)
2) Chlorobenzene(C6H5Cl) to Carbolic acid(Phenol-Hydroxybenzene)
Steps involved:
a)Convert Chlorobenzene to C6H5ONa (Sodium phenoxide) by treatment with conc. NaOH at 300 atm and 360 degrees C. (Substitution reaction)
360 C/300 atm
C6H5Cl---------------> C6H5ONa
conc. NaOH
b) Convert Sodium phenoxide to Carbolic acid(Phenol) by the addition of H+ ions in acidic medium of dilute H2SO4. (Substitution reaction)
H+ ions
C6H5ONa-----------------> C6H5OH