Question

Find the greatest number that will divide 129, 161 & 224 leaving the remainder 5,6 and 7

Answer 1

hi

Find the greatest number that will divide 129, 161 & 224 leaving the remainder 5,6 and 7

129 - 5 = 124

161 - 6 = 155

224 - 7 = 217

so the numbers are 124,155 and 217

hcf of 124,155 and 217

124 =  2 x 2 x 31

155 =  5 x 31

217 = 7 x 31

hcf = 31

hence 31 is the greatest number that will divide 129, 161 & 224 leaving the remainder 5,6 and 7

hope it helps u

:)

Answer 2

Heya !!!

129 - 5 = 124

161 - 6 = 155

224 - 7 = 217



New numbers are 124 , 155 and 217.


Now,

Prime factorisation of 124 = 2 × 2 × 31

Prime factorisation of 155 = 5 × 31

Prime factorisation of 217 = 7 × 31

Required Number = HCF (125,155,217) = 31



Hence,

The greatest Number that Divides 129 , 161 and 224 leaves remainder 5 , 6 and 7 is 31.

HOPE IT WILL HELP YOU...... :-)