find the greatest number that will divide 130,150, and 200 leaving remainders 2, 6 and 8 respectively?
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first subtract respective remainders from the numbers
next write product of prime numbers.
find greatest common divisor or highest common factor
next write product of prime numbers.
find greatest common divisor or highest common factor
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Answer:
The greatest number that will divide 128,144 and 192 completely, is the H.C.F. of these numbers is 16.
Step-by-step explanation:
The number divides 130,150and 200 leaving the remainder 2,6 and 8.
So, that number will divide (130-2), (150-6) and (200-8) completely.
Now, the greatest number that will divide 128,144 and 192 completely, is the H.C.F. of these numbers.
128=2*2*2*2*2*2*2
144=2*2*2*2*3*3
192=2*2*2*2*2*2*3
H.C.F. = 2*2*2*2= 16
The greatest number that will divide 128,144 and 192 completely, is the H.C.F. of these numbers is 16.
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