Question

Find the greatest number that will divide 148, 246 and 623 leaving remainders
4, 6 and 11 respectively.

Answer 1

↑ Here is your answer ↓
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HCF of the 148 - 4, 246 - 6 and 623 - 11 i.e HCF of 144, 240, 612 is the greatest number that leave remainders 4, 6 and 11 respectively.

$144 = 2 * 2 * 2 * 2 * 3;$

$240 = 2 * 2 * 2 * 2 * 3 * 5;$

$612 = 2 * 2 * 3 * 3 * 17$

i.e HCF is 12

Answer 2

HCF of the 148-4,246-6 and 623-11 i.e HCF of 144, 240, 612 is the greatest number that leave remainders 4,6 and 11 respectively.
144 = 2 x 2 x 2 x 2 x 3;
240 = 2 x 2 x 2 x 2 x 3 x 5;
612 = 2 x 2 x 3 x 3 x 17
i.e HCF is 12

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