find the greatest number that will divide 262 and 334 and leave a remainder 10 in each case .solve it
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Answered by
7
hi
aim : Find the greatest number that will divide 262 and 334 and leave a remainder 10 in each case .solve it
so,
262 - 10 = 252
334 - 10 = 324
so the numbers are 252 and 324
now lets find the hcf of 252 and 324
252 = 2 x 2 x 3 x 3 x 7
324 = 2 x 2 x 3 x 3 x 3 x 3
hcf = 2×2×3×3
hcf = 36
hence 36 is the greatest number that will divide 262 and 334 and leave a remainder 10 in each case
hope it helps u
:0
aim : Find the greatest number that will divide 262 and 334 and leave a remainder 10 in each case .solve it
so,
262 - 10 = 252
334 - 10 = 324
so the numbers are 252 and 324
now lets find the hcf of 252 and 324
252 = 2 x 2 x 3 x 3 x 7
324 = 2 x 2 x 3 x 3 x 3 x 3
hcf = 2×2×3×3
hcf = 36
hence 36 is the greatest number that will divide 262 and 334 and leave a remainder 10 in each case
hope it helps u
:0
vivekraj7:
ans is right
Answered by
2
Hi there !!
First leave the remainder 10
so ,subtract 262 -10 =252
334-10= 324
Now find hcf of 324 and 252
Thanks ❣️❣️
First leave the remainder 10
so ,subtract 262 -10 =252
334-10= 324
Now find hcf of 324 and 252
Thanks ❣️❣️
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