Question

Find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively. Give answers with full solution and with photos

Answer 1

Solution :-

Given : The greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.

These three number can be written as :

328 - 7 = 321

436 - 8 = 428

544 - 9 = 535

Now, By Prime factorisation :

321 = 3 × 107

428 = 2² × 107

535 = 5 × 107

HCF of 321, 428 and 535 = 107

Answer : 107 is the greatest number that will divide 328, 436 and 544 leaving remainder 7, 8 and 9 respectively.

Answer 2

• We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.

Now..

=> 328 - 7 = 321

=> 436 - 8 = 428

=> 544 - 9 = 535

Now.. we have to find the H.C.F. of 321, 428, 535

• HCF of 321 = 3 × 107

• HCF of 428 = 2 × 2 × 107

• HCF of 535 = 5 × 107

107 is common in 321, 428 and 535.

So, HCF is 107

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107 is the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively

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