Find the greatest number that will divide 37 and 53 leaving 5 as remainder in each case .
Answers
Answer:
Given:
The numbers are 37 and 53 which when divided by the greatest number leaves 5 as a remainder in each case
To Find:
The greatest number that will divide 37 and 53 leaving 5 as the remainder in each case
Solution:
(1). We will first subtract the remainder 5 from each given number i.e.,
37 - 5 = 32
53 - 5 = 48
(2). Now, we will find the H.C.F. of 32 and 48 by prime factorization method
32 = 2 × 2 × 2 × 2 × 2
48 = 2 × 2 × 2 × 2 × 3
∴ H.C.F of 32 and 48 = 2 × 2 × 2 × 2 = 16
Thus, the greatest number that will divide 37 and 53 leaving 5 as the remainder in each case is 16.
Given:
The numbers are 37 and 53 which when divided by the greatest number leaves 5 as a remainder in each case
To Find:
The greatest number that will divide 37 and 53 leaving 5 as the remainder in each case
Solution:
(1). We will first subtract the remainder 5 from each given number i.e.,
37 - 5 = 32
53 - 5 = 48
(2). Now, we will find the H.C.F. of 32 and 48 by prime factorization method
32 = 2 × 2 × 2 × 2 × 2
48 = 2 × 2 × 2 × 2 × 3
∴ H.C.F of 32 and 48 = 2 × 2 × 2 × 2 = 16
Thus, the greatest number that will divide 37 and 53 leaving 5 as the remainder in each case is 16.
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