Question

find the greatest number that will divide 989,1258 and 1359 leaving remainders 66, 51 and 10 respectively

Answer 1

Here is your Answer mate:-

So the number which divides 989, 1258 and 1359 leaving the remainders as 66, 51 and 10

Is the HCF of 989–66, 1258–51 and 1359–10

That is the HCF of 923, 1207 and 1349

So the process of finding the HCF is in the attachment

This is the long division method of finding the HCF

So the HCF of 923, 1207 and 1349 is 71.

Hence, the greatest number that will divide 989, 1258 and 1359 leaving the remainders as 66, 51 and 10 respectively is 71.

Hope it helps you

Thanks...

Answer 2

Answer:71

Step-by-step explanation: firstly find the HCF of 989–66, 1258–51 and 1359–10= 923, 1207 and 1349

The no. Found will be the ans that is 71