Find the greatest number which can divide 49 109 and169 and leaves the remainders of 4 in each case
Answers
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2
Answer:
5
Step-by-step explanation:
49 divided by 5 gives 45 with 5 into 7 and remains 4 and 109 leaves 4 and 169 leaves 4
Answered by
2
Given:
The numbers are 49, 109 and 169 which when divided by the greatest number leaves 4 in each case.
To find :
The greatest number which can divide 49, 109 and 169 and leaves the remainders of 4 in each case.
Solution:
To find the number, Subtract the remainder 4 from each number,
49 - 4 = 45
109 - 4 = 105
169 - 4 = 165
Let us find the H.C.F of 45, 105 and 165 by prime factorization method
45 = 3 × 3 × 5
105 = 3 × 5 × 7
165 = 3 × 5 × 11
Therefore, H.C.F of 45, 105 and 165 is 3 × 5 = 15.
The greatest number is 15.
Final answer:
The greatest number which can divide 49, 109 and 169 and leaves the remainders of 4 in each case is 15.
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