Question

find the greatest number which divide 33 ,60 and 84 leaving remainder of 6,6 and 3 respectively solve it

Answer 1

hi

aim ; Find the greatest number which divide 33 ,60 and 84 leaving remainder of 6,6 and 3 respectively solve it

so,

33 - 6 = 27

60 - 6 = 54

84 - 3 = 3 = 81

now the numbers are 27,54 and 81

so let us find the hcf of 27,54 and 81

=> 27 = 3*3*3

54 = 3*3*3*2

81 = 3* 3*3*3

so hcf = 3*3*3

hcf = 27

hence 27 is the greatest number which divide 33 ,60 and 84 leaving remainder of 6,6 and 3 respectively 

hope it helps u

:)

Answer 2

Hi there ☺️

The greatest no. 2 which 33 ,60 and 84
Leaving remainder 6,6 and 3
$33 - 6 = 27 \\ \\ 60 - 6 = 54 \\ \\ 84 - 3 = 81$

So find Hcf of 27 , 54 and 81

$27 = {3}^{3} \\ \\ 54 = 2 \times {3 }^{3} \\ \\ 81 = 3 ^{4}$

Common factor 3^3

Answer is 27

Thanks !!