Question

find the greatest number which divide the numbers 90,115 and 140 completely, when these numbers are increased by 1,2 and 3 respectively.

Answer 1

Numbers are 90+1, 115+2, 140+3
No.= 91, 117, 143
For finding the greatest number which divide these no. completely we have to find the HCF.....
91=13×7
117=3×3×13
143=11×13
HCF=13
GREATEAT NO. DIVIDES WITH THESE NO. IS 13.....
HOPE IT HELP U.....

Answer 2

Concept:

The greatest number by which two or more number can be divided is called HCF (Highest Common Factor) of that numbers.

Given:

Given numbers are 90,115, and 140. Numbers are increased by 1,2,3 respectively.

Find:

The greatest number which divide the numbers after increase.

Solution:

90 increased by 1 gives = 90+1 = 91

115 increased by 2 gives = 115+2 = 117

140 increased by 3 gives = 140+3 = 143

Now prime factorization of that numbers we get,

91 = 7*13

117 = 3*3*13

143 = 11*13

So the common factor for all three numbers is 13.

So HCF of 91,117, 143 is 13.

Hence 13 is the greatest number which divide the numbers 90, 115 and 140 completely when these numbers are increased by 1, 2 and 3 respectively.

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