find the greatest number which divided 615 and 963, leaving the reminder 6 in each case
Answers
Answered by
5
Hi,
number - remainder
615 - 6 = 609
963 - 6 = 957
find the HCF of 609 and 957
609 = 3 × 7 × 29
957 = 3 × 11 × 29
HCF ( 609 , 957 ) = 3 × 29 = 87
∴ 87 is the required number which divides
615 , 963 leaving the remainder 6 in each case.
I hope this helps you.
: )
number - remainder
615 - 6 = 609
963 - 6 = 957
find the HCF of 609 and 957
609 = 3 × 7 × 29
957 = 3 × 11 × 29
HCF ( 609 , 957 ) = 3 × 29 = 87
∴ 87 is the required number which divides
615 , 963 leaving the remainder 6 in each case.
I hope this helps you.
: )
Answered by
1
Answer:
Hope its helpful for you......
Attachments:
Similar questions