Find the greatest number which divides 1277 and 1368 leaving a reminder of 3 in each case.
Answers
Answered by
67
1277-3=1274, 1368-3=1365
Hence, HCF(1274,1365) will give us the required number.
By applying Euclid's Division Algorithm,
HCF(1274,1365): 1365=(1274 x 1) + 91
1274=(91 x 14) + 0
So, HCF(1274,1365) = 91
Therefore, the greatest number that divides 1277 and 1368 leaving remainder 3 in each case is 91.
Hence, HCF(1274,1365) will give us the required number.
By applying Euclid's Division Algorithm,
HCF(1274,1365): 1365=(1274 x 1) + 91
1274=(91 x 14) + 0
So, HCF(1274,1365) = 91
Therefore, the greatest number that divides 1277 and 1368 leaving remainder 3 in each case is 91.
Answered by
26
hcf of (1277-3) & (1368-3)
so it will be=(13★7)=91...
so it will be=(13★7)=91...
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