Question

Find the greatest number which divides 203 and 434 leaving remainder 5 in each case.

Answer 1

Answer:

33

Step-by-step explanation:

Given that the numbers 203 and 434 leaving remainder 5 in each case respectively.

The numbers that are exactly divisible are 203 - 5 = 198 and 434 - 5 = 429.

Prime factorization of 198 = 2 * 3 * 3 * 11

Prime factorization of 429 = 3 * 11 * 13.

HCF(198,429) = 3 * 11

                       = 33.

Therefore the largest number which divides 203 and 434 leaving remainder 5 in each case = 33.

Hope this helps!

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Answer 2

Answer:

33 is the answer.

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