Find the greatest number which divides 203 and 434 leaving remainder 5 in ea
case.
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The numbers that are exactly divisible are 203 - 5 = 198 and 434 - 5 = 429. Prime factorization of 429 = 3 * 11 * 13. = 33. Therefore the largest number which divides 203 and 434 leaving remainder 5 in each case = 33.
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Answer:
The numbers that are exactly divisible are 203 - 5 = 198 and 434 - 5 = 429. Prime factorization of 429 = 3 * 11 * 13. = 33. Therefore the largest number which divides 203 and 434 leaving remainder 5 in each case = 33
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