Math, asked by guddusinha7488, 1 month ago

Find the greatest number which divides 203 and 434 leaving remainder 5 in ea
case.​

Answers

Answered by shefalibarik43
0

Answer:

The numbers that are exactly divisible are 203 - 5 = 198 and 434 - 5 = 429. Prime factorization of 429 = 3 * 11 * 13. = 33. Therefore the largest number which divides 203 and 434 leaving remainder 5 in each case = 33.

Answered by geetur62
0

Answer:

The numbers that are exactly divisible are 203 - 5 = 198 and 434 - 5 = 429. Prime factorization of 429 = 3 * 11 * 13. = 33. Therefore the largest number which divides 203 and 434 leaving remainder 5 in each case = 33

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