Question

find the greatest number which divides 203 and 434 leaving remainder 5 in each case

Answer 1

The answer is Thirty-three 33

Answer 2

Question:

Find the greatest number which divides 203 and 434 leaving remainder 5 in each case.

Answer:

• 33

Solution:

Given the number 203 and 434 leaving remainder 5 in each case respectively:-

The numbers that are exactly divisible are:-

= 203 - 5 = 198

= 434 - 5 = 429

The prime factors of 198 and 429 are :-

= 198 = 2 × 3 × 3 × 1 × 1

= 429 = 3 × 11 × 13

★.HCF (198,429) = 3 × 11 = 33