Find the greatest number which divides 2053 and 434 leaving remainder 5 in each case
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Given that the numbers 203 and 434 leaving remainder 5 in each case respectively.
The numbers that are exactly divisible are 203 - 5 = 198 and 434 - 5 = 429.
Prime factorization of 198 = 2 * 3 * 3 * 11
Prime factorization of 429 = 3 * 11 * 13.
HCF(198,429) = 3 * 11
= 33
THERFORE THE NO. IS 33 WHICH DIVIDES BOTH BY LEAVING 5.
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