Math, asked by ayuban5309, 10 months ago

Find the greatest number which divides 2053 and 434 leaving remainder 5 in each case

Answers

Answered by PriyanshuBist2005
3

Given that the numbers 203 and 434 leaving remainder 5 in each case respectively.

The numbers that are exactly divisible are 203 - 5 = 198 and 434 - 5 = 429.

Prime factorization of 198 = 2 * 3 * 3 * 11

Prime factorization of 429 = 3 * 11 * 13.

HCF(198,429) = 3 * 11

= 33

THERFORE THE NO. IS 33 WHICH DIVIDES BOTH BY LEAVING 5.

I HOPE ITS HELPFUL TO YOU.

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