Question

Cos(2a-b) =1/ 2 and tan (3b - a) = 1, find value of sin (4a - 3b)

Answer 1

Answer:

cos(2a-b) = 1/2

cos(2a-b)=cos 60

2a-b=60 this is first equation

tan(3b-a)=1

tan(3b-a)=tan 45

3b-a=45 this is second equation

now substituting both the equation we get a =45 and b=30

Step-by-step explanation:

now sin(4a-3b)=sin(4×45-3×30)

that is sin(180-90)

sin90

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