Question

find the greatest number which divides 258 and 323 leaving remainders 2 and 3 respectively​

Answer 1

Answer:

It is given that a number divides 258 with remainder 2 and 323 with remainder 3. Hence 258-2 =>256 and 323-3 =>320 is divisible by this number. So we need to find the H.C.F. of 256 and 320. 256 =>2×2×2×2×2×2×2×2 and 320 =>2×2×2×2×2×2×5. Hence H.C.F. => 2×2×2×2×2×2 =>64. So the greatest number which divides 258 and 323 leaving remainders 2 and 3 respectively is 64.Hope it helps you.

Answer 2

find the greatest number which divides 258 and 323 leaving remainders 2 and 3 respectively​.

ans. 64

A number divides 258 with remainder 2 and 323 with remainder 3. let that number be x. x = 258-2 =256 and 323-3 =320 is divisible by x. So we need to find the H.C.F. of 256 and 320, which is 64, thus, the greatest number which divides 258 and 323 leaving remainders 2 and 3 respectively​ is 64.