find the greatest number which divides 3031 and 5055 leaving remainder 16 and 15 respectively
Answers
Answered by
1
Answer:
The greatest number obtained here is 154.
Solution:
Let the greatest number to find be a.
When 2011 is divided by a, remainder left = 9.
Thus, (2011-9) is divisible by a.
Hence, 2002 is divisible by a.
And, When 2623 is divided by a, remainder left = 5.
Thus, (2623-5) is divisible by a.
Therefore, 2618 is divisible by a.
Now to find a, we need to find out the "Highest Common Factor" or "H.C.F." of "2002 and 2618".
So, "H.C.F." of "2002 and 2618" is 154.
Hence, the greatest number is 154.
Answered by
5
Answer:. 45 will be the answer
Step-by-step explanation: 3031-16 and 5055-15 gives 3015 and 5040 respectively. Now take the hcf of 3015 and 5040 and the answer will be 45. Hope it helps.
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