find the greatest number which divides 615, 936 leaving remainder 9,5 respectively
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Therefore 87 is the greatest number which divides 615, 936 leaving remainder 9,5 respectively.
Step-by-step explanation:
In this question, since remainder is six, so we will subtract 6 from 615 and 963 i.e. 609 and 957. Then, we will find the H.C.F. of 609 and 957, that is going to be our answer.
957= 3×11×29
609= 3×3×29
So, H.C.F.= 3×29= 87
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