Math, asked by gango31, 10 months ago

Find the greatest number which divides 82 and 132 leaving 1 and 6, respectively as remainders WITH PROPER SOLUTIONS​

Answers

Answered by learner2201
1

Answer:

9

Step-by-step explanation:

x = 82, y =132

a=1, b = 6

(x-a),(y-b)

(82-1) , (132 -6)

81,126

HCF of 81, 126 is 9

Answered by YOGESHmalik025
4

answer

so , we need to find HCF

82 - 2 x 2 x 3 x7

132 - 2 x 2 x 3 x11

= 2 x 2 x 3

= 4 x 3

= 12 is answer

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