Find the greatest number which divides 82 and 132 leaving 1 and 6, respectively as remainders WITH PROPER SOLUTIONS
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Answered by
1
Answer:
9
Step-by-step explanation:
x = 82, y =132
a=1, b = 6
(x-a),(y-b)
(82-1) , (132 -6)
81,126
HCF of 81, 126 is 9
Answered by
4
❥ answer
so , we need to find HCF
82 - 2 x 2 x 3 x7
132 - 2 x 2 x 3 x11
= 2 x 2 x 3
= 4 x 3
= 12 is answer
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