find the greatest number which on dividing 1657 and 2037 leaves remainder 6 and 5 respectively
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Here is your answer dear⬇️⬇️
We will subtract 6 from 1657 and 5 from 2037
1657 - 6 = 1651
2037 - 5 = 2032
Now, we will find the HCF of 1651 and 2037
So,
1651 = 13×127
2037 = 2×2×2×2×127
Common factors = 127
![\large \blue {127 \: is \: the \: greatest \: number.} \large \blue {127 \: is \: the \: greatest \: number.}](https://tex.z-dn.net/?f=%5Clarge+%5Cblue+%7B127+%5C%3A+is+%5C%3A+the+%5C%3A+greatest+%5C%3A+number.%7D)
We will subtract 6 from 1657 and 5 from 2037
2037 - 5 = 2032
Now, we will find the HCF of 1651 and 2037
So,
1651 = 13×127
2037 = 2×2×2×2×127
Common factors = 127
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