Question

Find the greatest number which when divided by 12 16 24 and 36 leaves a remainder 7 in each case

Answer 1

For this particular sum we need to find the LCM of the given numbers.

The smallest number which when divided by 12 16 24 and 36 = LCM of 12 16 24 and 36

12 = 2×2×3

16 = 2×2×2×2

24 = 2×2×2×3

36 = 2×2×3×3

LCM = 144

The smallest number which divides 12 16 24 and 36 is 144. But we have a condition that it leaves a remainder of 7. So we add 7 to the LCM (144+7=151).

Hence the smallest number that when divided by 12 16 24 and 36 leaves a remainder 7 is 151.

Answer 2

Answer:

for this particular sum we need to find the LCM of the given number.

Step-by-step explanation:

12 = 2×2×3

16=2×2×2×2

24=2×2×2×3

36=2×2×3×3

LCM=144

The smallest number which divides 12 16 24 and 36 is 144.