Find the greatest number which when divided by 6 15 and 18 leave remainder 5 in each case
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Hope this helps, but....
There is no greatest number with that property!
The smallest positive number that leaves a remainder of 5 in each case is 5.
The lcm (lowest common multiple) of 6, 15 and 18 is 90.
So adding any multiple of 90 to 5 will give another number with the property that "when divided by 6, 15 and 18, it leaves a remainder of 5 in each case".
In other words, the numbers with that property are:
5, 95, 185, 275, 365,.... , 90k+5, .... etc.
Anonymous:
did
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