find the greatest number, which will divided both 564 and 630 to keep remainder 3 in both cases
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Answer:
11 is the correct answer
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Dividing a number x by y leaves a remainder 3, that means that y - 3 will be perfectly divisible by x.
So in this case, we need to find the highest common factor of 561 (564 - 3) and 627 (630 - 3).
Factorizing the two numbers:
561 = 3 × 11 × 17
627 = 3 × 11 × 19
We can see that the highest common factor here is 3 × 11 = 33. That is the answer to the question.
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