find the greatest nunber of six digits which is exactly divisible by 27 ;45;60;72;96
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0
Answer:
562744
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1
Answer:
Solution:-
LCM of 27,45,60,72 and 96= 4320
Greatest 6 digit number =99999
When we divide 999999 by 4320 we get the remainder==231.48
So,
The largest number will be=4320×231
=997920
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