Find the greather number which exactly divides the number 280and 1245,leaving remainder 4 and 3 respectively
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sub 4 from 280 & 3 from 1245
280-4=276 & 1245-3=1242
then find the h.c.f of 276 &1242
276= 2×2×3×23
1242=2×3×3×3×23
h.c.f= 2×3×23
h.c.f=138
280-4=276 & 1245-3=1242
then find the h.c.f of 276 &1242
276= 2×2×3×23
1242=2×3×3×3×23
h.c.f= 2×3×23
h.c.f=138
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