Find the group number and period number of element having atomic number 52.
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Answer:
group no. = 18-(Next inert gas - given atomic no.)
= 18-(54-52) = 18 - 2 = 16th group, oxygen family.
period = 5
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It's tellurium
it belongs to 16th group and 5th peroid
pls mark me as brainlist
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