Question

find the H.C.F by Euclid’s division algorithm of the numbers 1405, 1465, and

1530. )

Answer 1

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Answer 2

1405, 1465 and 1530

Now,
1405 < 1465

1465 = 1405 × 1 + 60
1405 = 60 × 23 + 25
60 = 25 × 2 + 10
25 = 10 × 2 + 5
10 = 5 × 2 + 0

HCF OF 1405 AND 1465 = 5


Again,
5 and 1530

5 < 1530

1530 = 5 × 306 + 0

$\huge\bold{Answer \:= \:5 }$