Find the H.C.F of 128, 136 & 512.
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Answered by
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128 = 2 x 2 x 2 x 2 x 2 x 2 x 2
136 = 2 x 2 x 2 x 17
512 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2.
Therefore HCF = 2 x 2 x 2 = 8
136 = 2 x 2 x 2 x 17
512 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2.
Therefore HCF = 2 x 2 x 2 = 8
Anonymous:
thanks
Answered by
1
Answer:
The final answer is 8.
Step-by-step explanation:
We need to find the HCF of 128, 136 and 512.
HCF is the highest common factor between two or more numbers. HCF is the maximum number of common numbers between two or more numbers such that each number can be divided in an equal manner.
First we need to find the common factors of the number by finding the prime factors of each number.
Factors of 128 = 2 * 2 * 2 * 2 * 2 * 2 * 2
Factors of 136 = 2 * 2 * 2 * 17
Factors of 512 = 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2
The common factors between all three numbers is 2 * 2 * 2 = 8
Hence HCF = 8
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