find the H C F of 135 and 225 and express it as a linear combination of 135 and 225
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225=135×1+90-(1)
135=90×1+45
90=45×2+0
HCF(225,135)=45
45=135-90×1 (from(1))
45=135-(225-135)×1 (since, 90=225-135)
45=-225+135×2
45=225(-1)+135(2)
45=225a+135b
Where, a=-1 and b=2
135=90×1+45
90=45×2+0
HCF(225,135)=45
45=135-90×1 (from(1))
45=135-(225-135)×1 (since, 90=225-135)
45=-225+135×2
45=225(-1)+135(2)
45=225a+135b
Where, a=-1 and b=2
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